Question

The drawing shows a sulfur dioxide molecule. It consists of two oxygen atoms and a sulfur atom. A sulfur atom is twice as massive as an oxygen atom. Using this information and the data provided in the drawing, find (a) the x coordinate and (b) the y coordinate of the center of mass of the sulfur dioxide molecule. Express your answers in nanometers (1 nm = 1.00 10^-9 m).

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(a) x_cmx =

(b) y_cmy =  

Answer 1

Solution given mass of solfor atom is twice of mass of oxygen atom let mass of oxygen atom is mo mass of solfor atom is amo m3=2m. Coordinad of atoms mi mQ · 60 60 inju 143nm > X

Coordinate of oxyger atom mi is (X,Y,) X=0,143 Sin 60º = 0./24 nm Y = 0.143 Cos60 20.0715 nm. Coordinate of oxygen atom Me is (X2, Y2 ) X220.143 Sin (-600) = -0.124 nm Y 2 20 143 Cos 60o = 0.0715 nm Coordinate of sulfure atom Mais (X21%) X 207.00

formula of center of mass X = 8m; X/ Yon = {miti mi' mixit M₂ X2+ M₂ X₂ Xem = - mama & Mol Xona mox 0.124 & mox 1 + 0.1247 of am. xo Mormo trmo Xom 20 Xem = 0 Ang у m, y, t m, y, - Т, У, тут ), ), Tam - M. Xo.0715 & Moxo.o715 +2m.xo moemo tamo 280.0715 0.0715 = 0.0358 nm Yoma 4 (6) Yon = 0.0358 nm Ans.