Question

Calculate the volume of 0.25 M sodium chloride solution, in ml, that must be diluted to prepare 50.00 mL of a 0.025 M NaCl so
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Answer #1

Number of moles of NaCl = molarity * volume of solution in L

Number of moles of NaCl = 0.025 * 0.05 = 0.00125 mole

molarity of NaCl = number of moles of NaCl / volume of solution in L

0.25 = 0.00125 / volume of solution in L

volume of solution in L = 0.00125 / 0.25 = 0.00500 L

1 L = 1000 mL

0.00500 L = 5.00 mL

Therefore, the volume of NaCl = 5.00 mL

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