Question

I have a 0.125 M sodium oxide solution

a) 15.25 mL of this is diluted to 100.00 mL total volume. What is the concentration of the new solution?

b) I now want to make 75.00 mL of a 20.00 mM solution. What volume of the 0.125 M solution must be diluted to 75.00 mL to make this?

c) What is the concentration of sodium ions in the 0.125 M sodium oxide solution?

Answer 1

- Sol.) Given, Sodium oxide (NGO) :- Stock Concentration, me = 0.125 m (a) Stock Vdeme Ve = 15.25 mL diluted Volume V2 = 100.00 mL let diluted concentration = M₂. a foo dilution, . Me v = make 3 m = mv, _ 0.125 m x 15.25 ml 100.00 ML = m = 0.0191 Mi 1 (Ang (6) diluted volume, V₂ = 75.00 mL diluted concentration, M = 20.00mm = 80.00x/0-3 m • my = Mak » V, = Mau Scanned with CamScanner M

= = 75.00 mL *20.00x103 m 0.125 m 2 = 12.0mL (Ang) (c) I : Let Il no. of moles of is 0.125 given Solution, m as no. of moles = concentration x Volume. 3) moles of Na, O = 0.125m*PL = 0.125 moles. 1 mol Nao have S As peo formula = Q mol Nations Lof smpound - 2 0.125 mol Nao have = 2*0.185 mol Nations = 0.25 mol Nations. So, Nation concentration, = 0.25 mol = 0.25 m - 1L (And Scanned with CamScanner