Question

The solubility of Ce(IO3)3 in a 0.14-M KIO3 solution is 1.3 x 10-7 mol/L. Calculate Ksp for Ce(IO3)3 - Ksp = Submit Answer Try Another Version 10 item attempts remaining

Answer 1

Q1. Ce(IO₃)₃

K_sp = [Ce³⁺][IO₃^-]³

K_sp = (1.3 x 10^-7 M) * (0.14 M + 1.3 x 10^-7 M)³

K_sp = (1.3 x 10^-7 M) * (0.14 M)³

K_sp = 3.6 x 10^-10

Q2. Ca₃(PO₄)₂

K_sp = [Ca²⁺]³[PO₄^3-]²

1.3 x 10^-32 = (s)³ * (0.16 M + s)²

where s = molar solubility

assuming s << 0.16 M

1.3 x 10^-32 = (s)³ * (0.16 M)²

s³ = (1.3 x 10^-32) / (0.16 M)²

s³ = 5.08 x 10^-31

s = (5.08 x 10^-31)^1/3

s = 8.0 x 10^-11 mol/L

solubility of solid Ca₃(PO₄)₂ = 8.0 x 10^-11mol/L

Q3. (a.) AgNO₂

(b.) Mn(CN)₂

Q4. (a) water

Solubility = 0.0105 mol/L

(b) 0.17 M Pb(NO₃)₂

Solubility = 2.6 x 10^-3 mol/L

(c) 0.017 M NaBr

Solubility = 5.7 x 10^-3 mol/L