Question

When 100.0 mL of 2.00 M Ce(NO3)3 is added to 100.00mL of 3.00M KIO3, a precipitate...

When 100.0 mL of 2.00 M Ce(NO3)3 is added to 100.00mL of 3.00M KIO3, a precipitate of Ce(IO3)3 (s) forms. Calculate the equilibrium concentrations of Ce3+ and IO- in this solution. Ksp Ce(IO3)3=3.2x10^-10

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Answer

[Ce3+] = 0.50029M

[IO3​​-] = 0.00086M

Explanation

Initial concentration of Ce3+ = 2.00M /(200ml/100ml) = 1.00M

Initial concentration of IO3- = 3.00M/( 200ml/100ml) = 1.50M

consider the complete formation of Ce(IO3)3

Ce3+(aq) + 3IO3-(aq) -------> Ce(IO3)3(s)

3mole of IO3- reacts with 1mole of Ce3+

1.50M of IO3- react with 0.50M of Ce3+

after completion of reaction

Concentration of Ce3+ = 0.50M

Concentration of IO3- =  0

Now , consider the solubility equilibrium of Ce(IO3)3

Ce(IO3)3(s) <-------> Ce3+(aq) + 3IO3-(aq)

Ksp = [Ce3+] [IO3-]3 = 3.2 ×10-10

Initial concentration

[Ce3+] = 0.50

[IO3-] = 0

change in concentration

[Ce3+] = + x

[IO3-] = + 3x

Equilibrium concentration

[Ce3+] = 0.50 + x

[IO3-] = 3x

so,

(0.50 + x) ( 3x)3 = 3.2 ×10-10

solving for x

x = 0.0002872M

Therefore,

at equilibrium

[Ce3+] = 0.50 + ( 0.0002872) = 0.50029M

[IO3-] = 3× (0.0002872) = 0.00086M

Add a comment
Know the answer?
Add Answer to:
When 100.0 mL of 2.00 M Ce(NO3)3 is added to 100.00mL of 3.00M KIO3, a precipitate...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT