(b) What is E°cell for the reaction 2MnO4- + 16H+ + 5Pb → 5Pb2+ + 2Mn2+ + 8H2O?
(b) What is E°cell for the reaction 2MnO4- + 16H+ + 5Pb → 5Pb2+ + 2Mn2+...
A galvanic cell at a temperature of 25.0°C is powered by the following redox reaction: 2MnO4-(aq) + 16H+(aq) + 5Pb(s) -> 2Mn2+(aq) + 8H2O(l) + 5Pb2+(aq) Suppose the cell is prepared with 2.08M MnO4- and 1.77M H+ in one half-cell and 1.82M Mn2+ and 1.13M Pb2+ in the other. Calculate the cell voltage under these conditions. Do not round intermediate calculations. Round your answer to 3 significant digits.
For the reaction 5H2O2 + 2MnO4- + 6H+ ----> 2Mn2+ + 5O2+ 8H2O, the experimentally dtermined rate of disappearance of MnO4-is 2.2x10-3 M/s. Calculate the reaction rate.
For the reaction 5H2O2 + 2MnO4- + 6H+ → 2Mn2+ +5O2 + 8H2O•The experimentally determined rate of disappearance of MnO4- is 2.2x10-3 M/s •Write out the relative rates for all chemicals involved in the reaction.
For the reaction 5H2O2 + 2MnO4- +6H+ → 2Mn2+ +5O2 + 8H2O The experimentally determined rate of disappearance of MnO4 is 2 2x10-3 M/s. Calculate the reaction rate. Enter the value only. The units of the value you enter wanted to enter the value 0.063, enter either 0.063 or 6.3E-2.
Consider the reaction : 2MnO4- + 5H2O2 + 6H+ --> 2Mn2+ +5O2 +8H2O. If it takes 36.44 mL of 0.01652 M KMnO4 solution are required to oxidize 25.00 mL of a H2O2 solution, Calculate the molarity of the H2O2 solution.State your final answer using 4 Sigfigs.
Consider the following two reactions involving oxalic acid. 2MnO4− + 5H2C2O4 + 6H+ → 2Mn2+ + 10CO2 + 8H2O H2C2O4 + 2OH− → C2O42− + 2H2O What volume of 0.0100 M KMnO4 solution will titrate a solution prepared from 46.0 mg of H2C2O4? What volume of 0.0100 M NaOH solution will titrate a solution prepared from 46.0 mg of H2C2O4?
QUESTION 6 In the balanced redox reaction below, 16H* (aq) + 2 MnO4 (aq) +502042-(aq) + 2Mn2+ (aq) + 8H2O(0) +10C02(0) label the following: A.C B.C2042 • What atom is reduced? C. Mn04 - # What reactant is the reducing agent? D. Mn E. O F. H G.
2Mn2+ +5H3AsO4⇌5HAsO2+2MnO4-+ 6H++ 2H2OIn the above redox reaction, use oxidation numbers to identify the element oxidized, the element reduced, the oxidizing agent and the reducing agent.2Cl2 +5Sb2O5+ 6H+ ⇌10SbO++4ClO3-+ 3H2OIn the above redox reaction, use oxidation numbers to identify the element oxidized, the element reduced, the oxidizing agent and the reducing agent.2MnO4-+3N2H4+ 4H2O⇌6NH2OH+ 2MnO2+ 2OH-In the above redox reaction, use oxidation numbers to identify the element oxidized, the element reduced, the oxidizing agent and the reducing agent.
A solution containing 0.190.19 M Pb2+Pb2+ , 1.5×10−61.5×10−6 M Pb4+Pb4+ , 1.5×10−61.5×10−6 M Mn2+Mn2+ , 0.190.19 M MnO−4MnO4− , and 0.900.90 M HNO3HNO3 was prepared. For this solution, the balanced reduction half‑reactions and overall net reaction shown can occur. 5[Pb4++2e−↽−−⇀Pb2+]5[Pb4++2e−↽−−⇀Pb2+] ?∘+=1.690 VE+°=1.690 V 2[MnO−4+8H++5e−↽−−⇀Mn2++4H2O]2[MnO4−+8H++5e−↽−−⇀Mn2++4H2O] ?∘−=1.507 VE−°=1.507 V 5Pb4++2Mn2++8H2O↽−−⇀5Pb2++2MnO−4+16H+5Pb4++2Mn2++8H2O↽−−⇀5Pb2++2MnO4−+16H+ A. Determine ?∘cellEcell∘, Δ?∘ΔG∘, and ?K for this reaction. ?∘cell=Ecell∘= V Δ?∘=ΔG∘= J ?=K= B. Calculate the value for the cell potential, ?cellEcell, and the free energy, Δ?ΔG, for the given conditions....
a Choose the balanced equation for the following half-reaction, which takes place in acidic solution MnO4 (aq)Se2 (aq) -> Mn2(aq) Se(s) O 16H (aq)2Mn04- (aq)5Se2 (aq) ->2Mn2 (aq) 6H20()5Se(s) O16H (aq)2MnO4- (aq)5Se2 (aq) -2Mn2 (aq) 8H20(1) 5Se(s) 16H+ (aq)MnO4 (aq) 5Se2(aq) - Mn2(aq) +8H20(l) 5Se(s) O16H (aq)MnO4- (aq) 5Se2 (aq) -2Mn2(aq) + 8H2O(l)5Se(s) bChoose the balanced equation for the following half-reaction, which takes place in acidic solution: S2Os2(aq)CI (aq) SO42(aq) Cl2 (aq) S2O82(aq)2CI (aq) 2SO42(aq) Cl2(aq) S2O82-(aq)C (aq) -2SO42-(aq) 2Cl2...