Question

6. A piece of 155.0 g aluminium metal at 120°C was placed in a constant pressure calorimeter of negligible heat capacity containing 300.0 g of water at 20°C. Calculate the final temperature of the system (the aluminium metal and the water) in °C: given the specific heat of aluminium metal = 0.90 J/g °C, and that of water 4.184 J/g °C

Answer 1

let the final tempor of the system is T mass of aluminium metal (Max) = 1559m tempris (The) = 1200=393 K mass of water (mike) = 300gm tempor. " (Tito) = 20°c = (20+273) = 293 K Specific heat of aluminium (SAI) = 0.95/ge " ' , water (Sto) = 4.189 3/9°c from the principle of calorimetry Heat released = Heat acceptance m gained : MAJ Sae* (-5+120) = m 40 x 5 max (T-20) w, 155 x0.9 x (120-1) = 300x4.184* (T-20) av, 16740 - 139.5T = 255:27-25104 av1394.7 T = 42844 er, T=30°C - Final temps is 3oć