Question

1. Use the experimentally-determined reduction potentials above to compute cell potentials (voltages) for the following cells
0 0
Add a comment Improve this question Transcribed image text
Answer #1

I Sol:- Given reactions Niat tre Feat thi Experimental standard At anode : Fe-qe > Feet (Ecell) (Eu -0.16V -0.45V Cathode i NAnode: Mg - 2e ² Mght Experimental Ecell) -1.200 0.300 Stondard (Ecell) -2.37V_ -0.26V. Cathode: Nift toe * Ni Experimented :Experimental standard Ni2+ + Fe Fe2t+ Ni Sraget the Zn + Niet 0.46V 1.500 0.19v 2.110 Ni2+ + Mg Zn²+ N í -0.gov -0.50v. 2 Exp

Add a comment
Know the answer?
Add Answer to:
1. Use the experimentally-determined reduction potentials above to compute cell potentials (voltages) for the following cells....
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Cell Potential and Equilibrium Standard reduction potentials The equilibrium constant, K, for a redox reaction is...

    Cell Potential and Equilibrium Standard reduction potentials The equilibrium constant, K, for a redox reaction is related to the standard cell potential, Ecel, by the equation Reduction half-reaction (V) Ag+ (aq) + e-→Ag(s) Cu2+ (aq) + 2e-→Cu(s) 0.34 Sn (a) 4e-Sn(s 0.15 2H' (aq) + 2e-→H2 (g) Ni2+ (aq) + 2e-→Ni(s)-0.26 Fe2+ (aq) + 2e-→Fe(s)-0.45 Zn2+ (aq) + 2e-→Zn(s)-0.76 Al3+ (aq) +3e-→Al(s) -1.66 Mg2+ (aq) + 2e-→Mg(s) -2.37 0.80 n FEcell where n is the number of moles of electrons...

  • Consider the voltaic cell and reduction half potentials: Zn(s) | Zn 2+(aq) (0.100 M) || Ni2+(aq)...

    Consider the voltaic cell and reduction half potentials: Zn(s) | Zn 2+(aq) (0.100 M) || Ni2+(aq) (1.50 M) | Ni(s) Zn 2+ (aq)/Zn (s) E o = - 0.760 V Ni2+ (aq)/Ni (s) E o = - 0.230 V a) Sketch the voltaic cell represented with the above line notation. Label the anode and cathode and indicate the half-reactions occurring at each electrode and the species present in each solution. Also indicate the direction of electron flow (3 marks). b)...

  • predicted voltage 1,2,3? ulations Part I: Voltaic Cells A. Cell Potentials Using a Zn(s)/Zn (aq) Reference...

    predicted voltage 1,2,3? ulations Part I: Voltaic Cells A. Cell Potentials Using a Zn(s)/Zn (aq) Reference Electrode Complete the following table using your mean values for PartI A, and assigning a reference voltage of 0.00 volts for the reduction of Zn2 to Zn. Put the voltages in increasing order Half-Reaction Standard Reduction Potential at 25 °C, Volts Zn (aq) + 2e Zn (s) 0.00 Fers +7 0.30 0.5 Phess B.Cell Potentials Using the Table Above Redox Couple predicted voltage observed...

  • Mcasured Cell Potentials of Redo x Couples from cells A1. A2, Bl. B2, and Unknown #1 Redox Measur...

    Mcasured Cell Potentials of Redo x Couples from cells A1. A2, Bl. B2, and Unknown #1 Redox Measured Anode Anode Reaction Cathode Cathode Reaction CouplePotential Cu-Zn 10.qqv|Zn |2n→ (Al-B2) Cu-Pb Pb-Zn (BI-B2) 0-46V Fe-Pb Fe-Zn Cu-Fe (AI-A2) Zn-Unk#1 (B2-A3) 0.3Iv Unkel Assuming that the reduction potential for Zn2 (0.10 M/Zn is equal to -0.79 V, calculate the reduction potentials for the remaining cells: Cu (0.10 M/Cu 0.2ov Calculation: 95 0- 0.71-0.20V zn ls) 2 ทั้า(o.1o)11 Fe2+Co.10m) 1 Fecz) Fe (0.10...

  • Lab11_PP_147-156... * 5 79 Calculations Part I:Voltaic Cells A. Cell Potentials Using a Zn(s)[Zn2+ (aq) Reference...

    Lab11_PP_147-156... * 5 79 Calculations Part I:Voltaic Cells A. Cell Potentials Using a Zn(s)[Zn2+ (aq) Reference Electrode Complete the following table using your mean values for Part 1 A, and assigning a reference voltage of 0.00 volts for the reduction of Zn?t to Zn. Put the voltages in increasing order. Half-Reaction Standard Reduction Potential at 25 °C, Volts Zn2+ (aq) + 2e → Zn (s) 0.00 0.328 0.443 0.907 observed voltage 0.469 percent error B. Cell Potentials Using the Table...

  • Calculate the standard free-energy change at 25 ∘C for the following reaction: Mg2+(aq) + Zn(s) → Mg(s) + Zn2+(aq) Expre...

    Calculate the standard free-energy change at 25 ∘C for the following reaction: Mg2+(aq) + Zn(s) → Mg(s) + Zn2+(aq) Express your answer to three significant figures and in units of kJ/mol. Consider constructing a voltaic cell with one compartment containing a Zn(s) electrode immersed in a Zn2+ aqueous solution and the other compartment containing an Al(s) electrode immersed in an Al3+ aqueous solution. What is the spontaneous reaction in this cell? Group of answer choices Zn + Al3+ → Al...

  • Mcasured Cell Potentials of Redo x Couples from cells A1. A2, Bl. B2, and Unknown #1...

    Mcasured Cell Potentials of Redo x Couples from cells A1. A2, Bl. B2, and Unknown #1 Redox Measured Anode Anode Reaction Cathode Cathode Reaction CouplePotential Cu-Zn 10.qqv|Zn |2n→ (Al-B2) Cu-Pb Pb-Zn (BI-B2) 0-46V Fe-Pb Fe-Zn Cu-Fe (AI-A2) Zn-Unk#1 (B2-A3) 0.3Iv Unkel Assuming that the reduction potential for Zn2 (0.10 M/Zn is equal to -0.79 V, calculate the reduction potentials for the remaining cells: Cu (0.10 M/Cu 0.2ov Calculation: 95 0- 0.71-0.20V zn ls) 2 ทั้า(o.1o)11 Fe2+Co.10m) 1 Fecz) Fe (0.10...

  • Never mind, i have found the correct answer. Standard reduction potentials for the Zn2+/Zn and Mg2+/Mg...

    Never mind, i have found the correct answer. Standard reduction potentials for the Zn2+/Zn and Mg2+/Mg couples are -0.76 and -2.37 V, respectively. The galvanic cell below uses the half-cells Mg2+IMg and Zn2+1Zn, and a salt bridge containing KCl(aq). The voltmeter gives a positive voltage reading. voltmeter salt bridge CD-> + | The identities of A and D, respectively, are Zn and K+ Mg and Cl- Zn and Ci- Mg and K+

  • While performing Lab 11, Electrochemistry, students connected 1 M solutions of the following metals and used...

    While performing Lab 11, Electrochemistry, students connected 1 M solutions of the following metals and used electrodes to monitor the cell potential. Using the table of theoretical values and what you know of the metals to fill in the blanks below. When writing equations: Use spaces only before and after a plus sign. For example, the reaction: Fe2+ + 2e - → Fe would be entered as: Fe^2+ + 2e. → Fe Galvanic Cell Consisting of: Zn²+ + 2e -...

  • Separate galvanic cells are made from the following half-cells: cell 1: H+(aq)/H2(g) and Pb2+(aq)/Pb(s) cell 2:...

    Separate galvanic cells are made from the following half-cells: cell 1: H+(aq)/H2(g) and Pb2+(aq)/Pb(s) cell 2: Fe2+(aq)/Fe(s) and Zn2+(aq)/Zn(s) Which of the following is correct for the working cells? Standard reduction potentials, 298 K, Aqueous Solution (pH = 0): Cl2(g) + 2e --> 2C1-(aq); E° = +1.36 V Fe3+(aq) + e --> Fe2+(aq); E° = +0.77 V Cu2+(aq) + 2e --> Cu(s); E° = +0.34 V 2H+(aq) + 2e --> H2(g); E° = 0.00 V Pb2+(aq) + 2e --> Pb(s);...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
Active Questions
ADVERTISEMENT