Consider the following reaction:
2NO2(g) ⟶ N2O4(g)
first calculate Kp of the reaction
Kp = (PN2O4) / (PNO2)2
Kp = (1.62) / (0.39)2 = 1.62 / 0.1521
Kp = 10.65
now
G = - RTlnK
R = 8.314 J/molK
T = 298 K
K = 10.65
G = - 8.314 x 298 x ln 10.65
G = - 5860 J
G = 5.86 kJ
Consider the following reaction: 2NO2(g) ⟶ N2O4(g) Part B Calculate AG at 298 K if the...
15. Consider the reaction 2 NO2(g) N2O4(g) . (a) Using Gf N2O4(g) = 97.79 kJ/mol and Gf NO2(g) = 51.3 kJ/mol, calculate G° at 298 K. kJ (b) Calculate G at 298 K if the partial pressures of NO2 and N2O4 are 0.35 atm and 1.60 atm, respectively. kJ 16. Consider the reaction given below. H2(g) + F2(g) 2 HF(g) (a) Using thermodynamic data from the course website, calculate G° at 298 K. kJ (b) Calculate G at 298 K...
For the reaction at 298 K, 2NO2 g → N2O4 g the values of ΔHo and ΔSo are -58.0 kJ and -177 J/K, respectively. What is the value of ΔG nonstandard at 298 K when the concentration of N2O4 is 1.69 M and the concentration of NO2 is 2.75 M? Remember to answer in correct units. ΔG=
Consider the reaction 2 NO2(g) N2O4(g) . (a) Using ΔGf N2O4(g) = 97.79 kJ/mol and ΔGf NO2(g) = 51.3 kJ/mol, calculate ΔG° at 298 K. ______ kJ (b) Calculate ΔG at 298 K if the partial pressures of NO2 and N2O4 are 0.45 atm and 1.55 atm, respectively. _____ kJ
Calculate ΔG at 298 K if the partial pressures of NO2 and N2O4 are 0.40 atm and 1.64 atm , respectively. please explain. thanks in advance
Consider the reaction 2 NO2(g) →N2O4(g) .(a) Using ΔGfN2O4(g) = 97.79 kJ/mol and ΔGf NO2(g) = 51.3 kJ/mol, calculate ΔG° at 298 K.kJ(b) Calculate ΔG at 298 K if the partial pressures of NO2 and N2O4 are 0.25 atm and 1.30 atm, respectively.kJ
Dinitrogen tetroxide decomposes to nitrogen dioxide: N2O4(g)→2NO2(g)ΔHorxn= 55.3kJ At 298 K, a reaction vessel initially contains 0.100 atm of N2O4. When equilibrium is reached, 58% of the N2O4 has decomposed to NO2. What percentage of N2O4 decomposes at 380 K ? Assume that the initial pressure of N2O4 is the same (0.100 atm).
Question text Calculate the equilibrium constants, KpKp and KcKc for the equilibrium reaction N2O4(g)⇄2NO2(g)N2O4(g)⇄2NO2(g) at 298 K. N2O4(g)N2O4(g) NO2(g)NO2(g) S0S0 (J/K/mol) 304.29 240.06 ΔfH0ΔfH0 (kJ/mol) 9.16 33.18 Select one or more: A. Kp=9.23Kp=9.23 , Kc=12.3Kc=12.3 B. Kp=0.563Kp=0.563 , Kc=0.33Kc=0.33 C. Kp=0.144Kp=0.144 , Kc=0.0058Kc=0.0058 D. Kp=0.355Kp=0.355 , Kc=1.23
For the reaction: 2NO2 (g) ↔ N2O4 (g) at 298 K, The value of ∆H⁰ and ∆S⁰ are -58.03 kJ and -176.6 J/K, respectively. (a) What is the value of ∆G⁰ at 298 K? (b) At what temperature would this process be spontaneous?
Consider the reaction: N2O4(g) ⇄ 2NO2(g) Kp = 80 In which of the following systems will the reaction proceed in a direction to use up some of the NO2 (from right to left in the above equation). Partial Pressure N2O4 Partial pressure NO2 X 0.0020 atm 0.400 atm Y 0.0040 atm 0.800 atm Z 0.0040 atm 0.300 atm A. Y and Z only B. Z only C. Y only D. X, Y, and Z E. X and Y only...
Dinitrogen tetroxide decomposes to nitrogen dioxide: N2O4(g)→2NO2(g) ΔrH∘=55.3kJmol−1 At 298 K, a reaction vessel initially contains 0.100 bar of N2O4. When equilibrium is reached, 58% of the N2O4 has decomposed to NO2. What percentage of N2O4 decomposes at 389 K? Assume that the initial pressure of N2O4 is the same (0.100 bar). Please use bar and not atm.