Calculate ΔG at 298 K if the partial pressures of NO2 and N2O4 are 0.40 atm and 1.64 atm , respectively. please explain. thanks in advance
Calculate ΔG at 298 K if the partial pressures of NO2 and N2O4 are 0.40 atm...
Consider the reaction 2 NO2(g) N2O4(g) . (a) Using ΔGf N2O4(g) = 97.79 kJ/mol and ΔGf NO2(g) = 51.3 kJ/mol, calculate ΔG° at 298 K. ______ kJ (b) Calculate ΔG at 298 K if the partial pressures of NO2 and N2O4 are 0.45 atm and 1.55 atm, respectively. _____ kJ
Consider the reaction 2 NO2(g) →N2O4(g) .(a) Using ΔGfN2O4(g) = 97.79 kJ/mol and ΔGf NO2(g) = 51.3 kJ/mol, calculate ΔG° at 298 K.kJ(b) Calculate ΔG at 298 K if the partial pressures of NO2 and N2O4 are 0.25 atm and 1.30 atm, respectively.kJ
For the dimerization of nitrogen dioxide, ΔG° = −4.7 kJ at 25°C. 2 NO2(g) ⟶ N2O4(g) Calculate ΔG for this reaction if the partial pressures of NO2 and N2O4 are both 0.38 atm. (R = 8.31 × 10−3 kJ/K) a. -10.86 kJ b. -11.36 kJ c. -15.12 kJ d. -11.07 kJ e. -7.10 kJ
Consider the following reaction: 2NO2(g) ⟶ N2O4(g) Part B Calculate AG at 298 K if the partial pressures of NO2 and N204 are 0.39 atm and 1.62 atm , respectively. Express the free energy in kilojoules to two decimal places. PO AQ R o aj ? AG = Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining
For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. For the reaction 2NO(g)+O2(g)↽−−⇀2NO2(g) the standard change in Gibbs free energy is Δ?°=−72.6 kJ/mol . What is ΔG for this reaction at 298 K when the partial pressures are ?NO=0.500 atm , ?O2=0.400 atm , and ?NO2=0.750 atm ?
15. Consider the reaction 2 NO2(g) N2O4(g) . (a) Using Gf N2O4(g) = 97.79 kJ/mol and Gf NO2(g) = 51.3 kJ/mol, calculate G° at 298 K. kJ (b) Calculate G at 298 K if the partial pressures of NO2 and N2O4 are 0.35 atm and 1.60 atm, respectively. kJ 16. Consider the reaction given below. H2(g) + F2(g) 2 HF(g) (a) Using thermodynamic data from the course website, calculate G° at 298 K. kJ (b) Calculate G at 298 K...
Enough NO2 gas is injected into a cylindrical vessel to produce a partial pressure, Pxe, of 1.00 atm at 298 K. Calculate the equilibrium partial pressures of NO and N2O4, given 2 NO,(8)=1.0,(8) K, = 3.1 at 298 K (5 points) Enough NO2 gas is injected into a cylindrical vessel to produce a partial pressure, Pxe, of 1.00 atm at 298 K. Calculate the equilibrium partial pressures of NO and N2O4, given 2 NO,(8)=1.0,(8) K, = 3.1 at 298 K...
For the reaction at 298 K, 2NO2 g → N2O4 g the values of ΔHo and ΔSo are -58.0 kJ and -177 J/K, respectively. What is the value of ΔG nonstandard at 298 K when the concentration of N2O4 is 1.69 M and the concentration of NO2 is 2.75 M? Remember to answer in correct units. ΔG=
For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. For the reaction 2NO(g)+O2(g)↽−−⇀2NO2(g) 2 NO ( g ) + O 2 ( g ) ↽ − − ⇀ 2 NO 2 ( g ) the standard change in Gibbs free energy is Δ?°=−72.6 kJ/mol Δ G ° = − 72.6 kJ/mol . What is ΔG for this reaction at 298 K when the partial pressures are ?NO=0.300 atm P NO...
For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. For the reaction N2 (g) + 3H2(g) -------> 2NH3(g) the standard change in Gibbs free energy is ΔG° = -72.6 kJ/mol. What is ΔG for this reaction at 298 K when the partial pressures are PN2 = 0.200 atm PH2 = 0.350 atm PNH3 = 0.850