For the reaction: 2NO2 (g) ↔ N2O4 (g) at 298 K, The value of ∆H⁰ and...

Question

Question

For the reaction: 2NO2 (g) ↔ N2O4 (g) at 298 K, The value of ∆H⁰ and ∆S⁰ are -58.03 kJ and -176.6 J/K, respectively.

(a) What is the value of ∆G⁰ at 298 K? (b) At what temperature would this process be spontaneous?

Answer 1

Answer #1

Ea we know that og = 6H-TAST AG = -58.034 18 (298+ - 176.6 = -5803052626.8. A0 = |- 5 403. 28 L = -5.40 kJ LLLLLLLLLLLLLLLLLL

Answer 2

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