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Suppose a shark of mass 2300 kg propels itself through the water with a forward thrust...

Suppose a shark of mass 2300 kg propels itself through the water with a forward thrust of 7100 N, resisted by an average drag force of 4200 N. (a) What is the net horizontal force on the shark? (b) What is the net work performed on the shark if it undergoes a horizontal displacement of 30 m? Recall Wnet= Fnetdcosθ. (c) If the shark has an initial velocity of vi = 12m/s, use the work-energy theorem to determine the shark's final velocity after the 30 m displacement described in part (b).

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Answer #1

Here we use the work energy theorem. We are given the force and displacement and intiial velocity,

Faer = 7100 N-4200 N 2900 N (2900 N)30v) Coso | 870001 J 03 00 M E***************************************************************************************************
This concludes the answers. If there is any mistake, let me know immediately and I will fix it....

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