Consider a solution of 30 grams of naphthalene in 1500 kg of benzene. Pure Benzene Mol....
1.A solution that contains 15.581 grams of benzene (molar mass = 78.1 g/mol) in 420 g of cyclohexane freezes at a temperature 9.50 ºC below the freezing point of pure cyclohexane. Calculate the molar freezing point depression constant, Kf, for cyclohexane. 2. The molar boiling point elevation constant for water is 0.512 ºC/m. What is the boiling point of a solution containing 673 g of water and 78.0 g of CaCl2? 3. A solution containing 32.0 g of an unknown...
The following information is given for lead at latm: AH yap(1740 °C) -178 kJ/mol AH fus(328 °C) = 4.77 kJ/mol boiling point = 1740 °C melting point = 328 °C specific heat solid= 0.130 J/gºC specific heat liquid = 0.138 J/gºC What is AH in kJ for the process of freezing a 26.3 g sample of liquid lead at its normal melting point of 328 °C. The following information is given for silver at latm: AHvap(2212 °C) = 254 kJ/mol...
5) The vapor pressure of liquid benzene is 20,170 Pa at 298.15 K, and AHvap = 30.72 kJ/mol at 1.00 atm. Calculate the normal boiling point (boiling point at 1.00 atm) of benzene.
Calculate the freezing point and boiling point of a solution containing 17.4 g of naphthalene (C10H8) in 112.0 mL of benzene. Benzene has a density of 0.877 g/cm3. Part A Calculate the freezing point of a solution. (Kf(benzene)=5.12∘C/m.) Part B Calculate the boiling point of a solution. (Kb(benzene)=2.53∘C/m.)
At 25C, the vapor pressure of pure benzene is 0.1252 atm. When 6.50 g of a sold sample of naphthalene,C10H8(128.17 g/mol), is dissolved in 76.0 g of pure benzene, C6H6, calculate the vapor pressure of benzene above the solution oy looL 2. Raoult's Law. At 25 °C, the vapor pressure of pure benzene is 0.1252 atm. When 6.50 g of a solid sample of naphthalene, C10Hg (128.17 g/mol), is dissolved in 76.0 g of pure benzene, C6H6 (78.0 g/mol), calculate...
A solution is made by dissolving 0.745 mol of nonelectrolyte solute in 853 g of benzene. Calculate the freezing point and boiling point of the solution. The normal freezing point of benzene is 5.49 °C and the normal boiling point of benzene is 80.1 °C. Assuming 100% dissociation, calculate the freezing point and boiling point of 0.570 mol of AgNO3 in 1.00 kg of water.
Calculate the freezing point and boiling point of a solution containing 20.0 g of naphthalene (C_10H_8) in 119.0 mL of benzene. Benzene has a density of 0877 g/cm^3. Calculate the freezing point of a solution (K_f (benzene) = 5.12 degree C/m) T_f = 2.54 Calculate the boiling point of a solution. (K_b (benzene) = 2.53 degree C/m) T_b =
Calculate the freezing point and boiling point of a solution containing 10.0 g of naphthalene (C10Hz) in 100.0 mL of benzene. Benzene has a density of 0.877 g/cm².
(4 Points) Gasoline is primarily a mixture of hydrocarbons and is sold with an octane rating that is based on a comparison with the properties of isooctane (CsHis), which has an enthalpy of vaporization of 35.8 kJ/mol and a normal boiling point of 98.2 °C. Determine the vapor pressure of isooctane on a very hot day when the temperature is 38.0 °C. 1. (4 Points) A 15.0 mg sample of a protein was dissolved in water to produce 5.00 mL...
2. Raoult's Law. At 25 °C, the vapor pressure of pure benzene is 0.1252 atm. When 6.50 g of a solid sample of naphthalene, C10Hg (128.17 g/mol), is dissolved in 76.0 g of pure benzene, C6H6 (78.0 g/mol), calculate the vapor pressure of benzene above the solution. [0.119 atm]