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0.65 v 0.36 v 0.35 v 0.40 v 1.36 v ClO2 OCI - C1O3 Cl2 9) ClO4 Using the above Latimer diagram answer the following questions
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Answer #1

Solution:

A) Strong oxidizing agent = Cl2

Because the reduction potential is more positive, hence it is easily reduced, therefore posses strong oxidizing power.

B) Potential for ClO3- to OCl-:

It is obtained by addition of potentials as,

ClO3- = ClO2-, E°= 0.35 V

ClO2- = OCl- , E°= 0.65 V

E°= 0.35 + 0.65 = 1.00 V

C) Cl2 undergoes disproportionation reaction becuase it is oxidised and reduced in the reactions.

Cl2 (0) = OCl- (+1) ---oxidatiom

Cl2(0) = Cl- (-1) ------(reduction)

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