Question

A point charge is placed in an area with a constant electric field as shown in the picture.  The point charge starts at rest.

E 3.8x1O6 N/C

A. What direction will the point charge start moving?  Why?  (looking for a sentence relating the directions of E and F and the sign of the charge.)

B. If the point charge moves 33 cm in 2.02x10^-5s, what is its mass?  [2.2x10^-8kg]

Answer 1

Concept:- here we use the property of charge in an electric field. We find the acceleration using equation of kinematics and then find the mass using Newton's law as shown below, ***************************************************************************************************
This concludes the answers. If there is any mistake, let me know immediately and I will fix it....

Concept: - here we use the property of charge in an electric field. We find the acceleration using equation of kinematics and then find the mass using Newton's law as shown below, A) force on a positive change is along the field. so the positive charge will more in the same direction as field B) d = v_t t + 1/2 at^2, v_i = 0 so, a = 25/t^2 = 2(0.33m)/(2.02 times 10^-5 s^2) = 1.62 times 10^9 m/s^2 Now a = F/m a = qE/m, put value of a, E and a to find m or, m = 2.2 times 10^-8 kg