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5B. (10 pts) If 2.846 g of pure chloroacetic acid (CHCICOOH. molar mass = 94.45 g/mol) is dissolved into water and then titra

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Equation: NaOH(aq) + CH,CICOOH(aq) →→NACH,CICOO(aq) +H20(1) No of moles of CH,CICOOH = 2846 g x 1 mol CH CI COOH 94.45 g 0.03

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