A 0.704 g of a pure acid, HA, is dissolved in water and an acid-base indicator added. The solution requires 33.78 mL of 0.256 M NaOH solution to reach the end point. What is the molar mass of the acid? HA(aq) + NaOH(aq) LaTeX: \longrightarrow⟶ NaA(aq) + H2O(aq)
Group of answer choices
81.4 g/mol
199 g/mol
145 g/mol
20.0 g/mol
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A 0.704 g of a pure acid, HA, is dissolved in water and an acid-base indicator...
A 0.704 g of a pure acid, HA, is dissolved in water and an acid- base indicator added. The solution requires 33.78 mL of 0.256 M NaOH solution to reach the end point. What is the molar mass of the acid? HA(aq) + NaOH(aq) → NaA(aq) + H2O(aq) 145 g/mol 81.4 g/mol 20.0 g/mol 199 g/mol Based on the equation below, which is correct? 2 C2H2(g) + 5 O2(g) → 4 CO2(g) + 2 H2O(g) C2H2(g) is reduced O2(g) is...
If 1.85 g MgO is combined with enough 1.00 M HCl to make 100.0 mL of solution in a coffee-cup calorimeter, the temperature of the resulting solution increases from 21.3°C to 35.7 °C. Calculate the enthalpy change for the reaction per mole of Mgo. Assume that the specific heat capacity of the solution is 4.18 J/g.K, and the density of the solution is 1.00 g/mL. A 0.704 g of a pure acid, HA, is dissolved in water and an acid-base...
5 g of an unknown acid, HA, is dissolved in enough water to provide 25.0 mL of solution. The pH of this HA (aq) solution is 2.1 . This solution is titrated with a 0.210 M NaOH solution. 60.2 mL of this NaOH solution is needed to reach the equivalence point. (a) What is the molar mass of HA? (b) What is the value of pKa for HA (aq)? (c) What is the pH at the equivalence point? (d) What...
2.77 g of an unknown acid, HA, is dissolved in enough water to provide 25.0 mL of solution. The pH of this HA (aq) solution is 1.33. This solution is titrated with a 0.250 M NaOH solution. 40.6 mL of this NaOH solution is needed to reach the equivalence point. (a) What is the molar mass of HA? (b) What is the value of pKa for HA (aq)? (c) What is the pH at the equivalence point? (d) What is...
2.77 g of an unknown acid, HA, is dissolved in enough water to provide 25.0 mL of solution. The pH of this HA (aq) solution is 1.33. This solution is titrated with a 0.250 M NaOH solution. 44.2 mL of this NaOH solution is needed to reach the equivalence point. (a) (2 marks) What is the molar mass of HA? (b) (2 marks) What is the value of pKa for HA (aq)? (c) (2 marks) What is the pH at...
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A 0.8746 g sample of an unknown acid, HA, is reacted with NaOH (aq). The reaction that occurs is as follows: HA (aq) + NaOH (aq) =====> NaA (aq) + H2O (l) If the complete reaction of the HA sample requires exactly 28.62 mL of 0.1927 M NaOH (aq), what is the molecular mass of HA ?
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