Problem: A 1.523 gram sample of KHP (molar mass=204.22 g/mol) was dissolved in 20.00 mL of...

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Answer 1

Answer #1

Number of moles = Mass in gram / Molar mass

Number of moles of KHP = 1.523 g / 204.22 g/mol = 0.00746 mol

From reaction, 1.0 mol of KHP requires 1.0 mol of NaOH to reach the end point then 0.00746 mol of KHP will required 0.00746 mol of NaOH.

Volume of NaOH solution required = 15.30 ml = 15.30 L / 1000 = 0.0153 L

Molarity = number of moles of solute / Volume of solution in Litre

Molarity of NaOH = 0.00746 mol / 0.0153 L = 0.4876 mol/L = 0.4876 M

Answer 2

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