Suppose that a simple random sample is taken from a normal population having a standard deviation...
Suppose that a simple random sample is taken from a normal population having a standard deviation of 11 for the purpose of obtaining a 95% confidence interval for the mean of the population. a. If the sample size is 16, obtain the margin of error. b. Repeat part (a) for a sample size of 81.
a. The margin of error for a sample size of 16 is ??? (Round to two decimal places as needed.)
b. The margin of error for a sample size of 81 is ???
Homework Answers
SolutionA:
z alpha/2 for 95%=1.96
n=16
population standard deviation =sigma=11
margin of error=zcrit*sigma/sqr(n)
=1.96*11/sqrt(16)
=1.96*11/4
margin of error =5.39
ANSWER:5.39
Solutionb:
z alpha/2 for 95%=1.96
n=81
population standard deviation =sigma=11
margin of error=zcrit*sigma/sqr(n)
=1.96*11/sqrt(81)
=2.396
margin of error=2.4
ANSWER:2.4
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