X = N(80,10^2)
Z = (X - mean)/10
a)
P(X< 60)
= P (Z<−2)=0.0228
b)
P(60 < X< 75)
=P ( −2<Z<−0.5 )
=0.2857
c)
P(X > 90)
= P (Z>1)
=0.1587
number of student
= 60* 0.1587
= 9.522
=9.52
eBook Exercise 6.23 (Algorithmic) The time needed to complete a final examination in a particular college...
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The time needed to complete a final examination in a particular college course is normally distributed with a mean of 80 minutes and a standard deviation of 10 minutes. Answer the following questions. (a) What is the probability of completing the exam in one hour or less? (b) What is the probability that a student will complete the exam in more than 60 minutes but less than 65 minutes? (c) Assume that the class has 50 students and that the examination period is...
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help Assignment Score: 9166 Submit Assignment for Grading Save Exercise 06.23 Question 17 of 20 Check My Work eBook The time needed to complete a final examination in a particular college course is normally distributed with a mean of 80 minutes and standard deviation of 10 minutes. Answer the following questions. a. What is the probability of completing the exam in one hour or less (to 4 decimals)? .0226 b. What is the probability that a student will complete the...