How many moles of Ne are contained in a 3.50 L tank at 155°C and 2.80...

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Answer 1

Answer #1

using the ideal gas equation

PV = nRT

P = pressure = 2.80 atm

V = volume = 3.50 L

T = temperature = 155 c = 428.15 K

R = 0.08206 L atm / k mol

substitute the values in the equation

n = PV / RT

n = 2.80 * 3.50 / 0.08206 * 428.15

n = 0.27893217 moles

answer => 0.279 moles

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Answer 2

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