Question

3. Write the complete and the net ionic equations for each acid-base reaction. a. HI (aq) + RbOH (aq) → b. HCHO2 (aq) + NaOH

I really need some help with number 3 and number 4 if you could also explain the steps I would greatly appreciate it!

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Answer #1

Solution:

3) A) Balanced equation will be:

HI(aq) + RbOH(aq) = RbI(s) + H2O(aq)

Total ionic equation will be:

H+(aq)+ I-(aq) + Rb+(aq) + OH-(aq) = RbI(s) + H+(aq) +OH-(aq)

Net ionic equation:

Rb+(aq) + I-(aq) = RbI(s)

B) Balanced molecular equation will be:

HCHO2(aq) + NaOH (aq) = NaCHO2 (aq) + H2O(l)

Total ionic equation:

HCHO2 (aq) + Na+(aq) + OH-(aq) = CHO2-(aq) + Na+(aq) + H2O(l)

Net ionic equation:

HCHO2(aq) + OH-(aq) = CHO2-(aq) + H2O(l)

C) Balanced equation will be:

HC2H3O2(aq) + NaOH(aq) = NaC2H3O2(aq) + H2O(l)

Total ionic equation:

HC3H3O2(aq) + Na+(aq) + OH-(aq) = Na+(aq) + C2H3O2-(aq) + H2O(l)

Net ionic equation:

HC3H3O2(aq) + OH-(aq) = C2H3O2-(aq) + H2O(l)

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