I really need some help with number 3 and number 4 if you could also explain the steps I would greatly appreciate it!
Solution:
3) A) Balanced equation will be:
HI(aq) + RbOH(aq) = RbI(s) + H2O(aq)
Total ionic equation will be:
H+(aq)+ I-(aq) + Rb+(aq) + OH-(aq) = RbI(s) + H+(aq) +OH-(aq)
Net ionic equation:
Rb+(aq) + I-(aq) = RbI(s)
B) Balanced molecular equation will be:
HCHO2(aq) + NaOH (aq) = NaCHO2 (aq) + H2O(l)
Total ionic equation:
HCHO2 (aq) + Na+(aq) + OH-(aq) = CHO2-(aq) + Na+(aq) + H2O(l)
Net ionic equation:
HCHO2(aq) + OH-(aq) = CHO2-(aq) + H2O(l)
C) Balanced equation will be:
HC2H3O2(aq) + NaOH(aq) = NaC2H3O2(aq) + H2O(l)
Total ionic equation:
HC3H3O2(aq) + Na+(aq) + OH-(aq) = Na+(aq) + C2H3O2-(aq) + H2O(l)
Net ionic equation:
HC3H3O2(aq) + OH-(aq) = C2H3O2-(aq) + H2O(l)
I really need some help with number 3 and number 4 if you could also explain...
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You may want to reference (Pages 557 - 545) SecuON 0.7 While Compleurig this problem. A 31,00 mL sample of an unknown H3PO, solution is titrated with a 0.130 M NaOH solution. The equivalence point is reached when 27.68 mL of NaOH solution is added What is the concentration of the unknown HPO, solution? The neutralization reaction is H3PO4 (aq) + 3NaOH(aq) + 3H2O(l) + Na3PO4 (aq) IVO AZ OO ? concentration Submit Request Answer
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