Question

5. Determine the oxidation states of the elements in the compounds listed. None of the oxygen-containing compounds are peroxides or superoxides. (A) H,PO (В) AI(ОH), (C) SeO2 6. Complete and balance the following acid-base equations: (A) A solution of HCIO, is added to a solution of LiOH. (B) Aqueous H2SO4 reacts with NaOH 7. Write the molecular, total ionic, and net ionic equations for the following reactions: (А) Са(ОН), (аq) + НС-Н,О,(aq) — (B) H,PO,(aq) CaCl,(aq) - 8. Write the balanced equation, then calculate the number of moles and the mass of Mg required to react with 5.00 g of HCl and produce MgCl, and Н. 9. H2 is produced by the reaction of 118.5 mL of a 0.8775-M solution of H3PO4 according to the following equation: 2Cr 2H,PO43H2 2CrPO4 How many grams of H, are produced?

Answer 1

Answers w © A) H₃PO, 06-0 no-H 4-0 Phosphorous oxidation state = 3(+12 + 3 + 4(-2) = 0 3 +2-8=0 x-5 = 0 x=+5 ALCOH) Aluminium onidation state = a +36-1) = 0 -3=0 n=+3 x+26-22=0 X-450 x=tle is the oxidation state " forse

la) moleculao equation is HC1o. t LiOH → Liclo + HLO laag caal can cel Tonic equation is H+C1o, +4+OH $ 4*+010. +48 z ll (99) can can, cany cant caal net Tonic equation 4t + oH HO (ag) 2097 e (99) 1997 r99) 17? Hy sou + NaOH >> N959 +2H0 102 ionic equation is 2H+ +50² +2.00 + 2014 at 2.0attson (aa) can can can . caar 'cas + -2 +Ho het Tonic equation is 24 t + Bogor & (aa) caal (e)

Caloh) +2HGHOL → Ca(Cato). A) can caan + Ponic eauation cat " # 20k + 24 +224 at 1240 caa) (aa) caan caa) PC and X2H,Ore) roa) net ionic equation qut+2015 - 2H₂O ca97 (99) (e) B) 2 H₂ Po t3cach Carpool (aa) cand + 6HCl ionk eauation (L') 2 64*+ 2po²+3 cat t6ci - Cocow), 18) . +6Httaci het lonie equation 3cat? +2 po co, cooo) 1993 ras t e (5)

mg + Q HCl - mgch + 2H₂ 24.305 2X16.46) 99.211 X2) olmo) 72.92 8lmol 49/mol omol according to eauation gimol 12.92 of Hcl requires 24.305 1 goting sg of Hill requires - got ng 5x24.305 121.525 = 1.666 g 72.92 72.92 72.92 10666 g of mg requires of mg . 0 . 24.305g neoles is one mole 1.666g of mg is - mole 1.666 *1 = 24.305 0.068 moles. -