What is the total charge of all the electrons in 9.11 L of liquid water?

Question

Question

Answer 1

Answer #1

The molar mass of an H2OH2O molecule is 2×1+1×16=182×1+1×16=18 grams
The total number of electrons per H2OH2O molecule is 2×1+1×8=102×1+1×8=10
The number of moles of H2OH2O in 1 kg of water is 1000/18=55.555...1000/18=55.555...
The number of moles of H2OH2O in 9.1 kg of water is =9.1*55.5555=505.555
The number of molecules of H2OH2O in 1 kg of water is 505.555...×6.022×10²³=31.84996815...×10²⁵
Therefore, the number of electrons in 9.1 kg of water is31.84996815×10²⁵×10*9.1=289.744×10²⁶
Finally, the total charge of those electrons is 289.744×10²⁶×−1.602176×10⁻¹⁹= -483.9304 ×10⁷Coulombs.

Answer 2

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