The molecular ion peak (M+) corresponds to m/z = 88
There is a peak at m/z = 73
88-73 = 15 corresponds to CH3-fragment.
There is a peak at m/z = 56
73-56 = 17 corresponds to OH-fragment.
The base peak at m/z = 43 corresponds to the propyl fragment (CH3CH2CH2).
The peak at m/z = 29 corresponds to the CH3-CH2 fragment.
Therefore, the structure of the molecule can be written as follows.
CH3-CH2-CH2-CH(OH)-CH3
Given the following data, determine the molecule. Homework #3 M Mass Spec Homework Problem #3 m/z...
Mass Spec Diethyl Phthalate Mass Spectrum Relative Intensity m/z MS diethylphthalate (note: major m/z values of 222, 193, 177, 149 are present) 3) Propose structures for TWO fragments in the mass spectrum. Note: the molecular ion peak at 222 m/z is NOT a fragment.
Use the data below from an electron impact mass spectrum of a pure compound to deduce its structure. Draw your structure. PART 1: m/z relative intensity 52 31 50 100 15 2 PART 2: m/z Relative intensity 17 1.6 16 100 15 89 14 20 13 11
Problem 115: Determine the molecule of
C7H12O
The IR, mass spec, CNMR and HNMR needs to be typed out not
handwritten, and the molecule needs to be a digital
representation as well. A base example is provided below:
________________________________________________________________________________________________________
Find and draw the molecule based on these charts (Drawing needs
to be digital and please type out answer)
Use an analysis of each graph and explain what numbers indicate
what groups.
Base Example
IR:
3500: O-H group
1750: Ester
Mass...
Determine the structure of Compound 2 using the Mass Spec, IR, C
NMR, H NMR, and Dept Experiments.
Splitting patterns are as follows from left to right: triplet, 5
peaks (unsure of name), septet (7), 4 peaks (unsure of name),
doublet
Compound 2 Mass Spec MT:M/2 = 164 Relative Intensity 25 50 75 125 150 100 m/z IR LO0 D 4000 3000 2000 1500 1000 500 HAVENUMBERI-i H NMR: ditto as compound 1 6 2 2 4 1 2 PPM...
Propose a reasonable structure for this compound based on the mass spec, IR, and NMR data. 100 Relative Intensity M+ 10 20 30 40 60 70 80 90 50 m/z LUU TRINETTRICET 4000 3000 2000 cm1 1500 1000 500 ЗН Зн 2H тттттттттттттттттт 11 10 9 8 7 6 5 4 ppm 200 180 160 140 120 80 60 40 20 100 ppm
Data Interpretation - Molecular Formula Based on the following microanalysis data and mass spectrum, determine the molecular formula for the molecule. Elemental Analysis: C, 57.84; H, 3.64; 0, 38.52 100 MS-NW-8142 80 60 Relative Intensity 40 20 o tommittit 25 50 75 125 150 100 m/z Select one: Cg H₂O4 O C5H.02 C4H₂O₂ C10H8O4 o C₂H₂O
Determine the structure of the compound using the Mass Spec, IR,
C NMR, H NMR, and Dept experiments .
Splitting pattern from left to right is as follows: triplet, 6,
5, 6, triplet
Compound 3 MS: M* = 81 Relative Intensity 10 20 30 40 70 80 90 50 60 m/z Microsoft Autog LOD TRANSMETTANCE1% 4000 2000 2000 1500 1000 HAVENUHBERI-1 1H NMR + ) PPM | 13C NMR 90 ' 80 ' 70 ' 60 ' 50 ' 40...
DESCRIBE PEAKS OF EACH NMR (Carbon 13 and PROTON 1H) and mass
spec on the one page
NMR Unknown_18 200 180 160 140 120 80 60 40 20 0 100 pom - 2 2 4 3 11 10 9 8 7 6 4 3 2 1 0 5 ppm - Relative Intensity 25 50 75 100 125 150 m/z
Draw the structure of the molecule given in the following
information:
Mass Spectrometry (not shown): (M) = 112 m/z Infrared Spectroscopy (not shown): 2860, 1699 cm 'H Nuclear Magnetic Resonance. 8H PPM c Nuclear Magnetic Resonance. 220 '200' 180 160 . 140 120 100.80.60.40.200
Problem 3. For a falling-head permeability test, the following are given: Length of soil spec imen 500 mm Area of the soil specimen 16 cm Area of the standpipe 0.97 cm2 Head differences at time t 0 is 760 mm Head differences at time t 8 min is 410 mm a) Determine the hydraulic conductivity of the soil b) What was the head differences at time t 5 min