Question

38 1.00 L o0M CHCOO (Ka- 1.8ox | mixed wth 0.Rs moles Solid NaOt (Assue no Volunt changewat will b The pHth eultpltim A) 4.1 B 4.26 4.74 5.35 ES.85

Answer 1

2 No. moles o CH DH in IL Solution 1 M Ct3 Coo H 1 4+ 1mot Li4- 1 mol Again ma les fNaoH in No. Solution= O-25 ma nentmalizatim neaction beoeen The be jiven and NaoH Can CH3 CONa +H20 CH2 COD H +Na 0H 1 mo) 1 tmol 0. 25 O-25 mo) O-25 mol After the neutmali 2a tion meaction the oemaining moles Cs H = (1- 0.25 )moles moles No. moles CH3Coo Na O.25

seution=1 L Vedume the Mdanity ofcCt L H 0.75 mol 1 L 0.75 M Molamity C3 cDNa O-25 mo 1 0.25 M Given -5 =180 X 10 Ka - log ka=-log (1-80 x t0-5 4.74 pka the given solution buften soution So, the pH of the sntion can be given aets as CH3DNA py =Pka + log 4.34 + 0.25 0.75

PH 4.74 - 0.48 = 4.26 S0, the onnect option is B. 4. 26 Ana 4.26 R