Question

A ball of dung is dropped from a height of 11.95 dung beetle meters (where one dung beetle meter is the length a dung beetle must travel to cover one meter). How many dung beetle seconds (where one dung beetle second is the amount of time it takes one dung beetle to travel one dung beetle meter at a rate of one meter per second) will it take for the ball of dung to reach the ground?

Answer 1

Here ,

let the time taken is t

acceleration , a = 9.8 m/s^2

Height , h = 11.95 m

Now, Using second equation of motion

h = 0.50 * gt^2

11.95 = 0.50 * 9.8 * t^2

solving for t

t = 1.56 s

the time taken for ball to fall is 1.56 dung beetle seconds