Question

If 0.252 g of Ni(NO3)2 6H20 reacts with 1.77 mmol of NaSCN and 1.65 mmol of PPH3 in the presence of excess triethyl orthoformate, how many grams (g) of [NIY2(PPh3)2] (Y = SCN or NCS) are expected? Answer: Check

Consider the overall balanced chemical equation:

Ni(NO₃)₂·6H₂O + 2 NaY + 2 PPh₃ + 6 HC(OC₂H₅)₃  → [NiY₂(PPh₃)₂] + 2 NaNO₃ + 12 C₂H₅OH + 6 HC(O)OC₂H₅

where Ph = C₆H₅ and Y = SCN or NCS (ambidentate ion).

MW of Ni(NO₃)₂·6H₂O = 290.8 g/mol

MW of NaSCN= 81.07 g/mol

MW of PPh3= 262.3 g/mol

MW of [NiY₂(PPh₃)₂] (Y = SCN or NCS) = 699.5 g/mol

Answer 1

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