answer is 2421
here p=0.35, margin of error=0.02
with (1- α)*100% confidence margin of error= z(α/2)*SE(p)
or, (1- 0.04)*100%=96% confidence margin of error= z(0.04/2)*sqrt(p(1-p)/n)
or, 0.02=2.0537*sqrt(0.35*(1-0.35)/n)
or,sqrt(0.35*(1-0.35)/n)=0.02/2.0537
or, sqrt(0.35*(1-0.35)/n)=0.0097
or, 0.35*(1-0.35)/n=0.000094
or, n=0.35*(1-0.35)/0.000094
or,n=2420.21 ( next whole number 2421)
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