Question

Due Sun 05/31/2010 11:59 pm You want to obtain a sample to estimate a population proportion. At this point in time, you have to be for the population proportion. You would like to be 99.9% confident that you esimate is within 0.25 population proportion. How large of a sample size is required? Hint: Shouldn't the answer be a WHOLE NUMBER Do not round mid-calculation. However, use a critical value accurate to three decimal places Points possible: 1 Unlimited attempts. Score on last attempt: 0. Score in gradebook: 0 Message instructor about this question Submit

Answer 1

For 99.9% CI z = 3.291 (rounded to 3 decimal places)

E = 0.002

p = 0.5

q = 0.5 (as previous estimates not given)

$\tiny n=\frac{z^2 *p*q}{E^2}=\frac{3.291^2 *0.5*0.5}{0.002^2} = 676917.56$

n = 676918 (rounded to nearest integer)

Please comment if any doubt. Thank you.