Suppose that in fall quarter I had 70% freshman and 30% other in my classes, 50% of the students got B’s and 50% got something else, and 60% of the students that got a B were freshman. What percentage of the freshman got B’s? Show work.
Solution :-
Given data :
Here we need to find out the percentage of the freshman got B’s.
Now consider as the class has "200 x" students.
Given as, 50% of the students got B’s.
Then, Number of students who got B's = 50% (200 x)
= 0.5 * 200 x
= 100 x
Number of students who got B's = 100 x
And given as, 60% of the students that got a B were freshman.
Then, Freshman ( who got B ) = 60% (100 x)
= 0.6 * 100 x
= 60 x
Freshman ( who got B ) = 60 x
And given as, 70% are freshman.
Then, Total Freshman = 70% (200 x)
= 0.7 * 200 x
= 140 x
Total Freshman = 140 x
Now, consider percentage of the freshman who got B’s.
i.e, Percentage of the freshman who got B’s = [Freshman ( who got B ) / Total Freshman ] * 100
= [ 60 / 140 ] * 100
= 0.4285 * 100
= 42.85 %
Percentage
of the freshman who got B’s = 42.85 % .
Suppose that in fall quarter I had 70% freshman and 30% other in my classes, 50%...
Suppose that in fall quarter I had 70% freshman and 30% other in my classes, 50% of the students got B’s and 50% got something else, and 60% of the students that got a B were freshman. What percentage of the freshman got B’s? Show work.
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