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Using only the 68-95-99.7 rule answer the following question. Let the variable Z be a z-score...

Using only the 68-95-99.7 rule answer the following question. Let the variable Z be a z-score of a normal distribution. Calculate P(Z ≤ 3).   Draw a picture of the situation first. Shade the area that corresponds to the desired proportion being sought.

Please explain how you would use the 68-95-99.7 rule to solve this. If you can, how would you solve this using technology rather than the rule?

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Answer #1

Solution :

Using Empirical rule,

P(\mu - 3\sigma< X < \mu + 3\sigma) = 99.7%

P(Z \leq 3) = 0.9985

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