Question

How would you prepare 77 mL of a solution 0.02 M from a stock solution of 1.3 M ?

(the volume of the water added is only an estimation. It would be correct if the density of the solution is equal to the density of the solvent, which is never the case, however the error in this case is quite small).

V of the stock solution = ?

V of water added ≈?

Answer 1

Water added :0:04h V, - 1994 tu=1.317 - Vi=9L Stock Solution Diluted solution catter Dilution) (be bore nitution) we know that Mili = Mq Uz Me = Molarity of stock solution = 1.34 1. volume of stock solution = ?he Mo= Molarity of diluted solution = 0.24 Vo - Volune ob Diluted solutions the = Maue 0:02x77 AL 1.3. . V = 1.184 Me .: Volune of stock solution 25.184 Volume of water added = Vz-v, = (27 – 1.134) ne =75816 hect water for 1.184 HL of stocka solution (1031) Diluted with 25.84 me of water, then nt Dilute solution Motivity is 0.0LM (77 KL). 14/14