Question

I got number 2 of the question wrong. can you please only do number 2 for me, when 8.00 S4N4 molecule and need to find grams of sulfur!

Determine the number af grams of sulfur preseted in each following 08.74 X 10 SRO melecule mot 1 (mol)= 8.748 16 atams. as 6022 2023 atoms 1.451 mol S2 2.32 of 64.14 O 16.00 80.4 g/mol (0) = 64.14 g 1.dsl mol 3.og 6 3.37 mole of so 8.32.07= 25608 8650g 8.00 Suny S = 4.32.07 - 128.3 g/mol 8.oomat. 128. 39 103.09 ③ 4.37 moles Soe s= 32.07 9/4 -4.37

Answer 1

@ Molal mass of Sama = 184-287 gmots So, 8.00 g of Sana = 800g 0.043410549 mol 184-287 g mot Now, each molecule of Samy contains 4 8' atoms So, 1 mol of Sand contains 4 mo sa So, 0.043410549 mol of sy ma contain 4 me 20.043410549 gol = 0.173642199 mol of s Nowo, molar mass of S'= 32.065 gomolio So, 00173642199 mol of S' = 0.173642199 molx 32.0653 = 5.567837124 9 of ' So, 200g of Ba Na contains 50567237124 9 5057 g offen mot i