kw= 1.00x10^-14 Determine the equilibrium constant for the following reaction: 4 H,0 = 4H+ + 4...

Question

Question

kw= 1.00x10^-14
Determine the equilibrium constant for the following reaction: 4 H,0 = 4H+ + 4 OH

Answer 1

Answer #1

the above reaction is....

4H2O $\rightleftharpoons$ 4H⁺ + 4OH^-

From the above reaction we can say [H⁺]=[OH^-], let say x

So for the above reaction equilibrium constant = $\frac{[H+]4*[OH-]4}{[H2O]4}$

But the [H₂O] will be neglected because its a pure liquid.

So now equilibrium constant will be = [H⁺]⁴*[OH^-]⁴

=X⁴ * X⁴

=X⁸

also K_w = [H⁺]*[OH^-] = 1.00 *10^-14

OR, X * X =1.00*10^-14

X² = 1.00*10^-14

Equilibrium constant = X⁸

= (X²)⁴

=(1.00*10^-14)⁴

=1.00*10^-56

Answer 2

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