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This question has multiple parts. Work all the parts to get the most points What arguments would you use to convince another
second question: what experiments vould be done to provide some evidence that the correct formulation of the element above?
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Answer #1

The correct argument for the above mention question would be that -

THE GROUPS CHARACTERISTICALLY FORM IONS WITH NOBLE GAS CONFIGURATION.GROUP 2A LOSES TWO ELECTRON AND GROUP 6A GAINS TWO ELECTRON.

The group 2A elements loses two electron from the s orbital to form stable nearest noble gas configuration.

the group 6A contains 4 electrons in the p orbitals and needs 2 electrons to form the nearest noble gas configuration.

Hence Mg loses two electrons which are accepted by the O to form Mg2+ and O2-.

This two ions are attracted to each other and form MgO.

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