Question

(1) _ Fe(s) + _ H20(g) Ⓡ_ Fe;0) + H () (B) __CH_(g) + _029) Ⓡ_CO2(g) + _H2O(g) (C)_KCIO, (s) ® KCI (s) + 0,(g) __CH4 (1) +_02(g) __CO2(g) + _H,0 (g) (@_CH_03 (1) + ___0,(9) ®__(9) + ___H_0 (1) (1) _NaN; (5) ®___ Na (s) + ___N. (9) (G) C,HN,O, ®_CO + N + H+O+ O, 2. Write and Balance the equations: (A) Aqueous calcium hydroxide reacts with aqueous sodium carbonate to produce solid calcium carbonate and aqueous sodium hydroxide. (6) Solid iron reacts with Oxygen gas to form solid Iron (II) oxide (c) Copper(II) sulfide is oxidized by molecular oxygen to produce gaseous sulfur trioxide and solid copper(II)oxide. The gaseous product then reacts with liquid water to produce liquid hydrogen sulfate as the only product. Write the two equations which represent these reactions. 3. Indicate what type, or types, of reaction each of the following represents: (precipitation, acid-base, and oxidation-reduction) (A) H2O(g) + C(s) — CO(g) +H (9) (B) 2KCIO,(s) — 2KCI(s) +30 (9) (C) Al(OH)3(aq) +3HCl(aq) — AICI,(aq) + 3H20(1) (D) Pb(NO),(aq) + H,SO (aq) — PbSO4(s) + 2HNO3(aq) 4. Silver can be separated from gold because silver dissolves in nitric acid while gold does not. Is the dissolution of silver in nitric acid an acid-base reaction or an oxidation-reduction reaction? Explain your answer.

Answer 1

+ 4H2292 3F6cs) + 4H2003 > Face (s) * (14&& + 302493 - 2 C02293 *** 2 ke03 (6) 2 kules, +30=(s) CH14 (23 +1202693 - 5035 20C9) 3 Hq O3 + 2/2002 (9) 3002 (gt 4H2O(g) 2 NaN3 (s) - Na(s) + 3 N² (9) 23 HS N309 --> 300, +3 N2 +5120 +22 © a) Ca(OH)2 + Na2CO (OH)2 (a + Na2CO3 - (99) > CaCO3 + 2NaOH (99) ) O 2 Fecs) + 0269) —2 FeO (3 s cusess + O2(g) cuo (s) + 50% (9) S03C9) + H2O() → H2 504 (2) A H₂O(g) + (cs) - CO(g) +H2 (9) displacement reaction B) De composition Yeaction 9 Double decomposition reactions DJ Double decomposition reaction or reaction 4 Agra + 6 HNO3 -> 3 AgNO3 + NO(g) + NO +34206) +5 Cag) + (aq) +250 (9) Oxidation - Reduction mposition reaction ☺