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1. The solution for a SHO (simple harmonic oscillator) is given as: x(t) = 0.1 sin(3t...

1. The solution for a SHO (simple harmonic oscillator) is given as: x(t) = 0.1 sin(3t − π/6) meters. Include appropriate units in your answers. (a) What is the amplitude of oscillation? (b) What is the initial position of the oscillator? (c) What is the maximum velocity of the oscillator and at what value of x does it occur? (d) What is the maximum acceleration of the oscillator and where does it occur? (e) What are the period and frequency of the oscillator? (f) If the mass of the oscillator is 0.025 kg what is the oscillator’s total energy?

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Answer #1

It is question of wave propagation. Kindly look carefully to formula used in the solution given in image form.

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