Question

ReviewI Constants TACTICS BOx 14.1 Identifying and analyzing simple harmonic motion Learning Goal: 1. If the net force acting on a particle is a linear restoring force, the motion will be simple harmonic motion around the equilibriunm To practice Tactics Box 14.1 Identifying and analyzing simple harmonic motion. position. 2. The position, velocity, and acceleration as a function of time are given in Synthesis 14.1 (Page 447) x(t)- Acos(2ft) Ug (t) = -(2rf)A sin( 2rft), A complete description of simple harmonic motion must take into account several physical quantities and various mathematical relations among them. This Tactics Box summarizes the essential information needed to solve oscillation problems of this type The equations are given here in terms of X, but they can be written in terms of y, or some other variable if the situation calls for it. 3· The amplitude A is the maximum value of the displacement from equilibrium. The maximum speed and the maximum magnitude of the acceleration are given in Synthesis 14.1 (Page 447): vmax-2nfA and amax-(2πf)2 A, respectively 4. The frequency f (and hence the period T-1/f) depends on the physical properties of the particular oscillator, but f does not depend on A. For a mass on a spring, the frequency is given by 5. The sum of potential energy plus kinetic energy is constant. As the oscillation proceeds, energy is transformed from kinetic into potential energy and then back again. ▼ Part A The position of a 40 g oscillating mass is given by (t) (2.0 cm) cos(10t), where t is in seconds. Determine the velocity at 0.40s Express your answer in meters per second to two significant figures. View Available Hint(s) m/s Submit

Answer 1