Question

Two point charges of the same magnitude but opposite signs are fixed to either end of the base of an isosceles triangle, as the drawing shows. The electric field at the midpoint M between the charges has a magnitude EM. The field directly above the midpoint at point P has a magnitude EP. The ratio of these two field magnitudes is EM/EP = 5.54. Find the angle α in the drawing.

I LJE 18.P.U51. My Notes Ask Your Teacher Two point charges of the same magnitude but opposite signs are fixed to the end of the base of an isosceles triangle, as the drawing shows. The electric field at the midport between the charges has a magnitude E. The field directly above the midpoint at point Phasmade The ratio of the two ma i s s e gein the drawing

Answer 1

Eisina At M electric field is F en . Elcosa Ezcus a 19 X X4 - q Now Ep. (EitĘ) cosa 5 x cosa en unco azry 24 x a un&o artyz Jazxyz - 249 UnCo Ca2+42 2 Allow EM = (artyz) EP QK (arty 2)2 azt 42 - az (aztu?)? (yaz+yz jº = cos3 . Mow Co g3 s.54 - Cosa (sy) - 0.5651496 2 22 55.5443° 2 55-60] Please reate dear. Thank q .