Question

A block rests on a frictionless horizontal surface and is attached to a spring.....

Chapter 10, Problem 81 A block rests on a frictionless horizontal surface and is attached to a spring. When set into simple harmonic motion, the block oscillates back and forth with an angular frequency of 9.8 rad/s. The drawing shows the position of the block when the spring is unstrained. This position is labeled "x=0m." The drawing also shows a small bottle located 0.080 m to the right of this position. The block is pulled to the right, stretching the spring by 0.050 m, and is then thrown to the left. In order for the block to knock over the bottle, it must be thrown with a speed exceeding Vy Ignoring the width of the block, find Om 0.050 m 0.080 Number Units the tolerance is +/-5%

Answer 1

- W=9.8 readis iw=flt a K= mc2 Now, by the conservation of energy mvut șik (0.050)2 = K (0.08032 1 m v. ² + 1/2 mw? (0.050)? Žm w2 (0.0802 Vo 19.8)"{10.080? (0.050)2} Vo = 0.612 m/s.