Question

Question 5 (1 point) A sample of gas has a volume of 735.0 mL at a pressure of 1.50 atm and a temperature of 112.0 °C. What is the final volume of the gas, in ml, at 0.550 atm and 62.0 °C? 2.30x103 ml O 1.10x103 mL 1.74x10 mL 3.62x103 mL 1.64x105 mL Question 6 (1 point) At STP, a 50.0 g sample of argon would occupy what volume, in Liters?

please note this question was ask to be clarified

Answer 1

PV = nRT and gas constant (R) moles of gas (n) are constant values PV = nR ila za = constant P2 V2 12 P = 0.550 am P = 1.50 am V = 735 mL I = 112°c = [112 + 273) K = 385k T2 = 62°c = 62 +973k = 335K PV = P2 V 2 1 Vz - PV Tz (1.50 am) * (735 ml) * (335k) (385k) x (0.550 alm) T, P2 V₂ = 1744 mL TV2 = 1.74 x 103 mL)