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Can you please explain me this question step by step?
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P2. (6-23) When the three blocks in Fig. are released from rest, they accelerate with a magnitude of 0.5m/s2. Block 1 has mass M, block 2 has 2M, and block 3 has 2M. What is the coefficient of kinetic friction between block 2 and the table? (Assume that the pulleys are frictionless.) (Ans: 0.37)
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Answer #1

Let pulley and string are massless.

The netwon 2nd Law-

F=ma, where m is mass and a is acceleration.

the kinetic friction force-

f​​​​​​k =mukN , where muk is kinetic friction coefficient and N is force of surface.T; 2. T, anA T arc Tension ih stih and a is acceberalishg = g-3 m/s 2 3 -r, = 10.3 8.-10.3)M 2(.HKg+-a) 8.3 - 4.15-a4.15-0.5 3 Proved

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