Homework Answers
given
B = 0.3 T
N = 20 turns
r = 5 cm = 0.05 m
R = 75 ohms
a) Voltage in the coil, V = N*A*dB/dt
= 20*pi*0.05^2*(0.3 - 0)/0.1
= 0.471 V
b) I = V/R
= 0.471/75
= 6.28*10^-3 A
c) Energy used up by the resistance of the coil,
E = Power dissipated*time
= I^2*R*dt
= (6.28*10^-3)^2*75*0.1
= 2.96*10^-4 J
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