Manganese(IV) oxide reacts with aluminum to form elemental manganese and aluminum oxide:
$$ 3 \mathrm{MnO}_{2}+4 \mathrm{Al} \longrightarrow 3 \mathrm{Mn}+2 \mathrm{Al}_{2} \mathrm{O}_{3} $$
What mass of Al is required to completely react with \(25.0 \mathrm{~g}\) \(\mathrm{MnO}_{2} ?\)
Answer
Manganese (IV) oxide reacts with aluminum to form elemental manganese and aluminum oxide: 3 MnO2+4...
Manganese(IV) oxide reacts with aluminum to form elemental manganese and aluminum oxide: 3MnO2+4Al→3Mn+2Al2O3 What mass of Al is required to completely react with 30.0 g MnO2?
elf Assessment 4.1 Manganese(IV) oxide reacts with aluminum to form elemental and oxide: You may want to reference (Page 142) Section 4.2 while completing this problem. Part A What mass of Al is required to completely react with 30.0 g Mn02? O 10.3 g Al O 124 g Al 776 g Al 5.82 g Al
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Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide. 4 HCI(aq) + MnO2(s) MnClj(aq) + 2H20) +C2(g) A sample of 38.7 g MnO2 is added to a solution containing 41.3 g HC. What is the limiting reactant? O HCI O Mno, What is the theoretical yield of Cl2? theoretical yield: g Cl If the yield of the reaction is 78.9%, what is the actual yield of chlorine? actual yield: gC2 Chlorine gas...