Question

Does this look correct, also what protons would have the most downfield shift

Answer 1

in Answer 'H NMR used to prove that the addition of HBr to Propene obey's Markcouni Kou's rule: The addition of HBT to propene give major product l-bromopropane. The IH NMR spectra ols 2-bromo propane show the two NMR signal because two types of Proton are present in 2- bromo propane. + C5-CH2-Chly Br LH@ + HBr 2-bromo propanel-bromo Propane 2- NMR Signal3-NMR signal 2- set of Proton 3-Set of Protons. On other band Antimarkovikov's product have 3 set ols Pootcom and it gives 3. NMR signal in it's IH NMR Spectrum. The addition lols HBrito poopene gives the product (2-bromo Propane) and the IH NMR spectra of this product gives only two NMR Signal. This show that product, has two set ols proten and this product Loomed according to Markovni kov's rule. Na Br most down bield Proton A. Proton is most down beld CH CH² CH2 Markovnikov's ® ® ® Product Proton because it attach to carbon, Hzis carbon is Integration splitting attached to electronegative Br multiplet ós septet atom. 1+ hou -I ektsect. Thus doublet electoom density ground this Pocton decreases and it required low magnehºc Lield bor absorphoon. Thay A Proten is most down Lield Protos

Anh: Markovnikov's Product CH₂CHh © ® thy Bo @ — most down kield Poutcos due to I ektect of Br Integrahicon Spliting triplet Sextet triplet