Question 3 (1 point) Given the following probability distribution, what is the expected value? Outcome P(Outcome) 31 0.12 25 0.08 2 0.06 14 0.21 40 0.00 6 0.53 Round to 2 decimal places as needed.
Let X be a random variable:
The probability distribution of X is:
X P(X=x)
31 0.12
25 0.08
2 0.06
14 0.21
40 0.00
6 0.53
The Expected value of X is:
Question 3 (1 point) Given the following probability distribution, what is the expected value? Outcome P(Outcome)...
Page 1: Question 1 (1 point) Given the probability that "she's up all night 'til the sun" OR "she's up all night for good fun" is 0.17, the probability that "she's up all night for good fun" is 0.27, and the probability that "she's up all night 'til the sun" is 0.47, what's the probability that "she's up all night 'til the sun" AND "she's up all night for good fun"? Round to 2 decimal places as needed. Your Answer:...
Question 4: Let X and Y be two discrete random variables with the following joint probability distribution (mass) function Pxy(x, y): a) Complete the following probability table: Y 2 f(x)=P(X=x) 1 3 4 0 0 0.08 0.06 0.05 0.02 0.07 0.08 0.06 0.12 0.05 0.03 0.06 0.05 0.04 0.03 0.01 0.02 0.03 0.04 2 3 foy)=P(Y=y) 0.03 b) What is P(X s 2 and YS 3)? c) Find the marginal probability distribution (mass) function of X; [f(x)]. d) Find the...
The probability distribution for the number of cards owned is given below: Number of cards: 0 1 2 3 4 5 Probability: 0.06 0.31 0.28 0.15 0.12 0.08 1) Show that above table is valid probability distribution 2)What is the expected value of number of cards owned by random person? 3)What is the probability that randomly selected person has less than 3 cards?
please help! Determine the expected count for each outcome n=400 1 2 3 4 P, 0.13 032 021 0.34 i The expected count for outcome 1 is (Round to two decimal places as needed) The expected count for outcome 2 s (Round to two decimal places as needed) The expected count for outcome is (Round to two decimal places as needed) The expected count for outcome dis (Round to two decimal places as needed)
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f size of n 4,900 from a binomial probability distribution with P 0.50, complete parts (a) through (e) below. Given a random sample EClick the icon to view the standard normal table of the cumulative distribution function. a. Find the probability that the number of successes is greater than 2,490. (Round to four decimal places as needed.) P(X 2,490) b. Find the probability that the number of successes is fewer than 2,425 P(X<2,425) (Round to four decimal places as needed....
Question 19 1 pts Given a population in which the probability of success is p=0.50, if a sample of 200 items is taken, Calculate the probability the proportion of successes in the sample will be between 0.46 and 0.53. (Round to four decimal places as needed.) 1 pts Question 20 What sample size is needed to estimate a population mean within plus or minus 70 of the true mean value using a confidence level of 90%, if the true population...
Given the following cumulative distribution of daily stock returns: What is the actual probability (based on the actual cumulative distribution) that daily return will be between -1.74% and +2.5227? a. 17.36% b. 84.94% c. 67.58% d. None of the above Actual Cumulative Cumulative Normal Return Value Frequency 0.10266 0.09414 0.08561 0.07709 0.06856 0.06003 0.05151 0.04298 0.03446 0.02593 0.0174 0.00888 0.00035 0.008175 0.016701 0.025227 0.033753 0.042279 0.050805 0.059331 0.067857 0.21% 0.21% 0.21% 0.21% 0.21% 0.42% 1.00% 3.14% 5.02% 11.09% 17.36% 30.33%...
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