Question

can’t figure any of this out, please help all of it

1-5. Match the functional group indicated by the arrow to the correct classification Quinine used to treat malaria 2. OH Hºme Church Hyco-OH Nysatin A, 3. CH, CH, OH A) primary alcohol B) secondary alcohol C) tertiary alcohol D) phenol E) thiol сн, он CH, OH не OH CONH2 -OH Tetracycline, an antibiotic 6-10. Given the following list of acid strengths of some medications, match the acid to the description: Questions Name Acid pka 6. Strongest Acid A pentacillamine HCH.NO,S 1.18 7. Weakest acid B. levadopa HC,H, NO. 2.13 8. Diprotic acid C. citric acid H.C.H.0, 3.08 9. Equal amounts of acid and conjugate base has a D. aspirin HCH,04 3.5 pH near 2 10. Its conjugate base is C, H, NO, E. methotrexate HC2H2 N.OS 4.8 11-15. Determine how many moles of each of the following compounds will react with 0.1 moles of NaOH Starting materials Products 11. KCI A) 0.2moles 12. HSO4 B) 0.1 moles 13. LiOH C) 0.05 moles 14. HNO, D) 0.033 moles 15. H.CH.O. (citric acid) E) O moles = no reaction 16-20 Match the situation or to the pH. 16. 0.28 M glucose (C,H,20) in water 17. pOH = 2 (aven cleaner) 18. [OH-] = 10" (lemon juice) 19. [H] =2.5 x 10 (rainwater) 20. POH=7.4 (milk) A) pH = 20 B) pH = 5.6 C) pH = 6,6 D) pH = 7.0 E) pH = 12,0 725flem aner) 20 21-25. Determine if the following solutions will be acidic, basic or neutral, if you can 21. 0.005 M H.CO. 22. 6.2 x 10' M NaHCO, 23. 0.5 M KCI 24. 0.28 M glucose CH1206 25. blood (pH = 7.4) A) acidic B) basic C) neutral D) cannot determine

Answer 1

Q 1 to 5
The OH group attached to primary carbon is primary alcohol, to secondary carbon is secondary alcohol and tertiary carbon is tertiary alcohol.
The OH attached to benzene directly is called phenol and an -SH group is called thiol.
1) This -OH is on secondary carbon (C with two C attached). so secondary alcohol.
2) secondary alcohol
3) tertiary alcohol
4)phenol
5) tertiary alcohol
Q6 to 10
The lower the pKa of acid, the stronger is the acid.

When pH of acid = pKa , then the ionisation is 50% , that is [acid] = [conjugate base] [Recollect Hendersen equation of bufer]

Thus

6) strongest acid - with lowest pKa - A.

7)weakest acid - highest pka - E

8)Diprotic acid - with two ionizable protons -E

9) equal amounts of acid and conjugate base near pH = 2 , that is its pKa is near 2 which is B

10) B

Conjugate base and acid differ by a proton.