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A manufacturing plant uses 6 specific machine tools. The life of the machine tool can be...
Question 7 The mean time between failures (often called MTBF) of the battery of a particular...
Question 7 The mean time between failures (often called MTBF) of the battery of a particular brand of computers is 450 hours. Assume that the time between failures is governed by an exponential distribution. What is the probability that the battery will fail (a) within 300 hours? (b) will last at least 500 hours? (c) will fail between 300 to 600 hours?
9. The service life of automobile tires is modeled by a normal curve; the Mean Time...
9. The service life of automobile tires is modeled by a normal curve; the Mean Time Between Failures (MTBF) is 20,000 miles and the standard deviation is 800 miles. Use Table B in Appendix B (page 868 and 869) to solve these problems. a. Determine the probability that a tire will fail before 22,000 miles. (2.5 point) Answer: b. Determine the probability that a tire will last at least 19,000 miles. (2.5 point) Answer: c. The manufacturer wishes to provide...
The life of a semiconductor laser at a constant power can be modeled by a Weibull...
The life of a semiconductor laser at a constant power can be modeled by a Weibull distribution with a mean of 7000 hours and a standard deviation of 600 hours. (a) What is the probability that a laser fails before 5800 hours? (b) What is the life in hours that 90% of the lasers exceed? (c) What should the mean life equal in order for 99% of the lasers to exceed 10,000 hours before failure? (d) A product contains three...
The time between failures of a laser in a machine, X, is exponentially distributed with a...
The time between failures of a laser in a machine, X, is exponentially distributed with a mean of 25,000 hours. In other words, 1 a= (failures/hour). 25,000 Exponential Distribution (pdf): f(x) = 1.0-\x, for x > 0. (a) What is the probability that the next failure occurs in 27,000 hours? (b) What is the expected time until the third failure? (c) What is the probability that the time until the third failure exceeds 25,000 hours?
sorry it is blurry The time between failures of a laser in a machine, X, is...
sorry it is blurry
The time between failures of a laser in a machine, X, is exponentially distributed with a mean of 25,000 hours. In other words, X= (failures/hour). 25,000 Exponential Distribution (pdf): f(x) = 1.e-r, for 2 > 0. (a) What is the probability that the next failure occurs in 27,000 hours? (b) What is the expected time until the third failure? (c) What is the probability that the time until the third failure exceeds 25,000 hours?
The compressive strength of samples of cement can be modeled by a normal distribution with a mean of 6000 kilograms per...
The compressive strength of samples of cement can be modeled by a normal distribution with a mean of 6000 kilograms per square centimeter and a standar deviation of 100 kilograms per square centimeter c) what strength is exceeded by 95% of the samples? The life of a semiconductor laser at a constant power is normally distributed with a mean of 7000 hours and a standar deviation of 600 hours a) what is the probability that a laser fails before 5000...
A large manufacturing plant uses lightbulbs with lifetimes that are normally distributed with a mean of...
A large manufacturing plant uses lightbulbs with lifetimes that are normally distributed with a mean of 1000 hours and a standard deviation of 50 hours. To minimize the number of bulbs that burn out during operating hours, all bulbs are replaced at once. How often should the bulbs be replaced so that no more than 1% burn out between the replacement periods? 884 584 501 O 484 381
(1)The field test data in respect of 172 components is as given below. In the life-testing...
(1)The field test data in respect of 172 components is as given below. In the life-testing of 100 specimens of a particular device, the number of failures during each time interval of twenty hours is shown in Table below. Estimate and Plot: the hazard function, failure density and reliability function. Time/Hours Failure 0-1000 59 1000-2000 24 2000-3000 3000-4000 4000-5000 5000-6000 29 30 17 13 (1) calculate the reliability of the system shown in the figure below 0.8 5 0.8 0.9...
QUESTION 6 The time to failure (in hours) of fans in a personal computer can be...
QUESTION 6 The time to failure (in hours) of fans in a personal computer can be modeled by an exponential distribution with rate 0.0005. Round your answers to 4 decimal places. (a) What proportion of fans will last at least 10000 hours? (b) What proportion of fans will last at most 8000 hours? QUESTION 7 Given the probability density function f(x)=(0.02^9 x^8*e^(-0.02x))/8! for x>0 and f(x)=0 otherwise. Determine the mean and variance of the distribution. Round the answers to the...
I Part b) (3 marks) The time between trains on a rail line at a specific...
I Part b) (3 marks) The time between trains on a rail line at a specific level crossing is well approximated by an exponential distribution with a mean of 1.2 hours between trains. I spend two hours at a picnic site overlooking the level crossing. When I arrive, it has been 1 hour since the last train went by. I count trains as they cross. What is the probability I will have counted at least three trains before I leave?
Question 7 The mean time between failures (often called MTBF) of the battery of a particular brand of computers is 450 hours. Assume that the time between failures is governed by an exponential distribution. What is the probability that the battery will fail (a) within 300 hours? (b) will last at least 500 hours? (c) will fail between 300 to 600 hours?
9. The service life of automobile tires is modeled by a normal curve; the Mean Time Between Failures (MTBF) is 20,000 miles and the standard deviation is 800 miles. Use Table B in Appendix B (page 868 and 869) to solve these problems. a. Determine the probability that a tire will fail before 22,000 miles. (2.5 point) Answer: b. Determine the probability that a tire will last at least 19,000 miles. (2.5 point) Answer: c. The manufacturer wishes to provide...
The life of a semiconductor laser at a constant power can be modeled by a Weibull distribution with a mean of 7000 hours and a standard deviation of 600 hours. (a) What is the probability that a laser fails before 5800 hours? (b) What is the life in hours that 90% of the lasers exceed? (c) What should the mean life equal in order for 99% of the lasers to exceed 10,000 hours before failure? (d) A product contains three...
The time between failures of a laser in a machine, X, is exponentially distributed with a mean of 25,000 hours. In other words, 1 a= (failures/hour). 25,000 Exponential Distribution (pdf): f(x) = 1.0-\x, for x > 0. (a) What is the probability that the next failure occurs in 27,000 hours? (b) What is the expected time until the third failure? (c) What is the probability that the time until the third failure exceeds 25,000 hours?
sorry it is blurry
The time between failures of a laser in a machine, X, is exponentially distributed with a mean of 25,000 hours. In other words, X= (failures/hour). 25,000 Exponential Distribution (pdf): f(x) = 1.e-r, for 2 > 0. (a) What is the probability that the next failure occurs in 27,000 hours? (b) What is the expected time until the third failure? (c) What is the probability that the time until the third failure exceeds 25,000 hours?
A large manufacturing plant uses lightbulbs with lifetimes that are normally distributed with a mean of 1000 hours and a standard deviation of 50 hours. To minimize the number of bulbs that burn out during operating hours, all bulbs are replaced at once. How often should the bulbs be replaced so that no more than 1% burn out between the replacement periods? 884 584 501 O 484 381
(1)The field test data in respect of 172 components is as given below. In the life-testing of 100 specimens of a particular device, the number of failures during each time interval of twenty hours is shown in Table below. Estimate and Plot: the hazard function, failure density and reliability function. Time/Hours Failure 0-1000 59 1000-2000 24 2000-3000 3000-4000 4000-5000 5000-6000 29 30 17 13 (1) calculate the reliability of the system shown in the figure below 0.8 5 0.8 0.9...
QUESTION 6 The time to failure (in hours) of fans in a personal computer can be modeled by an exponential distribution with rate 0.0005. Round your answers to 4 decimal places. (a) What proportion of fans will last at least 10000 hours? (b) What proportion of fans will last at most 8000 hours? QUESTION 7 Given the probability density function f(x)=(0.02^9 x^8*e^(-0.02x))/8! for x>0 and f(x)=0 otherwise. Determine the mean and variance of the distribution. Round the answers to the...
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