Question

Combining 0.360 mol Fe, O, with excess carbon produced 12.0 g Fe. Fe, O, +3C 2 Fe +3CO What is the actual yield of iron in moles? actual yield: mol What is the theoretical yield of iron in moles? theoretical yield: mol What is the percent yield? I percent yield: TOOLS х10

Answer 1

Number of moles of Fe = 12.0 g / 55.845 g/mol = 0.215 mole

Therefore, the actual yield of Fe = 0.215 mole

From the balanced equation we can say that

1 mole of Fe2O3 produces 2 mole of Fe so

0.215 mole of Fe2O3 will produce

= 0.215 mole of Fe2O3 *(2 mole of Fe / 1 mole of Fe2O3)

= 0.430 mole of Fe

Therefore, theoretical yield of Fe = 0.430

percent yield = (actual yield / theoretical yield)*100

percent yield = (0.215 / 0.430)*100

percent yield = 50.0 %